On rectangular constant in normed linear spaces

Fuente: arXiv
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Hauptverfasser: Paul, Kallol, Ghosh, Puja, Sain, Debmalya
Format: Preprint
Veröffentlicht: 2014
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author Paul, Kallol
Ghosh, Puja
Sain, Debmalya
author_facet Paul, Kallol
Ghosh, Puja
Sain, Debmalya
contents We study the properties of rectangular constant $ μ(\mathbb{X}) $ in a normed linear space $\mathbb{X}$. We prove that $ μ(\mathbb{X}) = 3$ iff the unit sphere contains a straight line segment of length 2. In fact, we prove that the rectangular modulus attains its upper bound iff the unit sphere contains a straight line segment of length 2. We prove that if the dimension of the space $\mathbb{X}$ is finite then $μ(\mathbb{X})$ is attained. We also prove that a normed linear space is an inner product space iff we have sup$\{\frac{1+|t|}{\|y+tx\|}$: $x,y \in S_{\mathbb{X}}$ with $x\bot_By\} \leq \sqrt{2}$ $\forall t$ satisfying $|t|\in (3-2\sqrt{2},\sqrt{2}+1)$.
format Preprint
id arxiv_https___arxiv_org_abs_1407_1353
institution arXiv
publishDate 2014
record_format arxiv
spellingShingle On rectangular constant in normed linear spaces
Paul, Kallol
Ghosh, Puja
Sain, Debmalya
Functional Analysis
46B20, 47A30
We study the properties of rectangular constant $ μ(\mathbb{X}) $ in a normed linear space $\mathbb{X}$. We prove that $ μ(\mathbb{X}) = 3$ iff the unit sphere contains a straight line segment of length 2. In fact, we prove that the rectangular modulus attains its upper bound iff the unit sphere contains a straight line segment of length 2. We prove that if the dimension of the space $\mathbb{X}$ is finite then $μ(\mathbb{X})$ is attained. We also prove that a normed linear space is an inner product space iff we have sup$\{\frac{1+|t|}{\|y+tx\|}$: $x,y \in S_{\mathbb{X}}$ with $x\bot_By\} \leq \sqrt{2}$ $\forall t$ satisfying $|t|\in (3-2\sqrt{2},\sqrt{2}+1)$.
title On rectangular constant in normed linear spaces
topic Functional Analysis
46B20, 47A30
url https://arxiv.org/abs/1407.1353