About sectional category of the Ganea maps

Fuente: arXiv
Enregistré dans:
Détails bibliographiques
Auteur principal: Doeraene, Jean-Paul
Format: Preprint
Publié: 2015
Sujets:
Accès en ligne:
Tags: Ajouter un tag
Pas de tags, Soyez le premier à ajouter un tag!
_version_ 1866913910501670912
author Doeraene, Jean-Paul
author_facet Doeraene, Jean-Paul
contents We first compute the James' sectional category (secat) of the Ganea map g_k of any map f in terms of the sectional category of f: We show that secat(g_k) is the integer part of secat(f)/(k+1). Next we compute the relative category (relcat) of g_k. In order to do this, we introduce the relative category of order k (relcat_k) of a map and show that relcat(g_k) is the integer part of relcat_k(f)/(k+1). Then we establish some inequalities linking secat and relcat of any order: We show that secat(f) <= relcat_k(f) <= secat(f) + k + 1 and relcat_k(f) <= relcat_(k+1)(f) <= relcat_k(f) + 1. We give examples that show that these inequalities may be strict.
format Preprint
id arxiv_https___arxiv_org_abs_1507_07752
institution arXiv
publishDate 2015
record_format arxiv
spellingShingle About sectional category of the Ganea maps
Doeraene, Jean-Paul
Algebraic Topology
55M30
We first compute the James' sectional category (secat) of the Ganea map g_k of any map f in terms of the sectional category of f: We show that secat(g_k) is the integer part of secat(f)/(k+1). Next we compute the relative category (relcat) of g_k. In order to do this, we introduce the relative category of order k (relcat_k) of a map and show that relcat(g_k) is the integer part of relcat_k(f)/(k+1). Then we establish some inequalities linking secat and relcat of any order: We show that secat(f) <= relcat_k(f) <= secat(f) + k + 1 and relcat_k(f) <= relcat_(k+1)(f) <= relcat_k(f) + 1. We give examples that show that these inequalities may be strict.
title About sectional category of the Ganea maps
topic Algebraic Topology
55M30
url https://arxiv.org/abs/1507.07752