Supercongruences for central trinomial coefficients

Fuente: arXiv
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Autori principali: Pan, Hao, Sun, Zhi-Wei
Natura: Preprint
Pubblicazione: 2020
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author Pan, Hao
Sun, Zhi-Wei
author_facet Pan, Hao
Sun, Zhi-Wei
contents For each $n=0,1,2,\ldots$, the central trinomial coefficient $T_n$ is the coefficient of $x^n$ in the expansion of $(x^2+x+1)^n$. Let $p>3$ be a prime, and let $n$ be any positive integer. In 2016, the second author conjectured that the quotient $(T_{pn}-T_n)/(pn)^2$ is always a $p$-adic integer. In this paper, we confirm this conjecture, and further prove that $$\frac{T_{pn}-T_n}{(pn)^2}\equiv\frac{T_{n-1}}6\left(\frac p3\right)B_{p-2}\left(\frac13\right)\pmod p,$$ where $(\frac p3)$ is the Legendre symbol and $B_{p-2}(x)$ is the Bernoulli polynomial of degree $p-2$.
format Preprint
id arxiv_https___arxiv_org_abs_2012_05121
institution arXiv
publishDate 2020
record_format arxiv
spellingShingle Supercongruences for central trinomial coefficients
Pan, Hao
Sun, Zhi-Wei
Number Theory
Combinatorics
For each $n=0,1,2,\ldots$, the central trinomial coefficient $T_n$ is the coefficient of $x^n$ in the expansion of $(x^2+x+1)^n$. Let $p>3$ be a prime, and let $n$ be any positive integer. In 2016, the second author conjectured that the quotient $(T_{pn}-T_n)/(pn)^2$ is always a $p$-adic integer. In this paper, we confirm this conjecture, and further prove that $$\frac{T_{pn}-T_n}{(pn)^2}\equiv\frac{T_{n-1}}6\left(\frac p3\right)B_{p-2}\left(\frac13\right)\pmod p,$$ where $(\frac p3)$ is the Legendre symbol and $B_{p-2}(x)$ is the Bernoulli polynomial of degree $p-2$.
title Supercongruences for central trinomial coefficients
topic Number Theory
Combinatorics
url https://arxiv.org/abs/2012.05121