Pythagoras number of quartic orders containing $\sqrt{2}$

Fuente: arXiv
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Autores principales: He, Zilong, Hu, Yong
Formato: Preprint
Publicado: 2022
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author He, Zilong
Hu, Yong
author_facet He, Zilong
Hu, Yong
contents Let $K$ be a quartic number field containing $\sqrt{2}$ and let $\mathcal{O}\subseteq K$ be an order such that $\sqrt{2}\in \mathcal{O}$. We prove that the Pythagoras number of $\mathcal{O}$ is at most 5. This confirms a conjecture of Krásenský, Raška and Sgallová. The proof makes use of Beli's theory of bases of norm generators for quadratic lattices over dyadic local fields.
format Preprint
id arxiv_https___arxiv_org_abs_2204_10468
institution arXiv
publishDate 2022
record_format arxiv
spellingShingle Pythagoras number of quartic orders containing $\sqrt{2}$
He, Zilong
Hu, Yong
Number Theory
11E12, 11E25, 11E16
Let $K$ be a quartic number field containing $\sqrt{2}$ and let $\mathcal{O}\subseteq K$ be an order such that $\sqrt{2}\in \mathcal{O}$. We prove that the Pythagoras number of $\mathcal{O}$ is at most 5. This confirms a conjecture of Krásenský, Raška and Sgallová. The proof makes use of Beli's theory of bases of norm generators for quadratic lattices over dyadic local fields.
title Pythagoras number of quartic orders containing $\sqrt{2}$
topic Number Theory
11E12, 11E25, 11E16
url https://arxiv.org/abs/2204.10468