The Kelley--Meka bounds for sets free of three-term arithmetic progressions

Fuente: arXiv
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Autori principali: Bloom, Thomas F., Sisask, Olof
Natura: Preprint
Pubblicazione: 2023
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author Bloom, Thomas F.
Sisask, Olof
author_facet Bloom, Thomas F.
Sisask, Olof
contents We give a self-contained exposition of the recent remarkable result of Kelley and Meka: if $A\subseteq \{1,\ldots,N\}$ has no non-trivial three-term arithmetic progressions then $\lvert A\rvert \leq \exp(-c(\log N)^{1/12})N$ for some constant $c>0$. Although our proof is identical to that of Kelley and Meka in all of the main ideas, we also incorporate some minor simplifications relating to Bohr sets. This eases some of the technical difficulties tackled by Kelley and Meka and widens the scope of their method. As a consequence, we improve the lower bounds for finding long arithmetic progressions in $A+A+A$, where $A\subseteq \{1,\ldots,N\}$.
format Preprint
id arxiv_https___arxiv_org_abs_2302_07211
institution arXiv
publishDate 2023
record_format arxiv
spellingShingle The Kelley--Meka bounds for sets free of three-term arithmetic progressions
Bloom, Thomas F.
Sisask, Olof
Number Theory
Combinatorics
We give a self-contained exposition of the recent remarkable result of Kelley and Meka: if $A\subseteq \{1,\ldots,N\}$ has no non-trivial three-term arithmetic progressions then $\lvert A\rvert \leq \exp(-c(\log N)^{1/12})N$ for some constant $c>0$. Although our proof is identical to that of Kelley and Meka in all of the main ideas, we also incorporate some minor simplifications relating to Bohr sets. This eases some of the technical difficulties tackled by Kelley and Meka and widens the scope of their method. As a consequence, we improve the lower bounds for finding long arithmetic progressions in $A+A+A$, where $A\subseteq \{1,\ldots,N\}$.
title The Kelley--Meka bounds for sets free of three-term arithmetic progressions
topic Number Theory
Combinatorics
url https://arxiv.org/abs/2302.07211