Unknotting nonorientable surfaces

Fuente: arXiv
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Autori principali: Conway, Anthony, Orson, Patrick, Powell, Mark
Natura: Preprint
Pubblicazione: 2023
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author Conway, Anthony
Orson, Patrick
Powell, Mark
author_facet Conway, Anthony
Orson, Patrick
Powell, Mark
contents Given a nonorientable, locally flatly embedded surface in the $4$-sphere of nonorientable genus $h$, Massey showed that the normal Euler number lies in $\lbrace -2h,-2h+4,\ldots,2h-4,2h \rbrace$. We prove that every such surface with knot group of order two is topologically unknotted, provided that the normal Euler number is not one of the extremal values in Massey's range. When $h$ is $1$, $2$, or $3$, we prove the same holds even with extremal normal Euler number. We also study nonorientable embedded surfaces in the 4-ball with boundary a knot $K$ in the 3-sphere, again where the surface complement has fundamental group of order two and nonorientable genus $h$. We prove that any two such surfaces with the same normal Euler number become topologically isotopic, rel. boundary, after adding a single tube to each. If the determinant of $K$ is trivial, we show that any two such surfaces are isotopic, rel. boundary, again provided that they have non-extremal normal Euler number, or that $h$ is $1$, $2$, or $3$.
format Preprint
id arxiv_https___arxiv_org_abs_2306_12305
institution arXiv
publishDate 2023
record_format arxiv
spellingShingle Unknotting nonorientable surfaces
Conway, Anthony
Orson, Patrick
Powell, Mark
Geometric Topology
57K40, 57N35, 57R67
Given a nonorientable, locally flatly embedded surface in the $4$-sphere of nonorientable genus $h$, Massey showed that the normal Euler number lies in $\lbrace -2h,-2h+4,\ldots,2h-4,2h \rbrace$. We prove that every such surface with knot group of order two is topologically unknotted, provided that the normal Euler number is not one of the extremal values in Massey's range. When $h$ is $1$, $2$, or $3$, we prove the same holds even with extremal normal Euler number. We also study nonorientable embedded surfaces in the 4-ball with boundary a knot $K$ in the 3-sphere, again where the surface complement has fundamental group of order two and nonorientable genus $h$. We prove that any two such surfaces with the same normal Euler number become topologically isotopic, rel. boundary, after adding a single tube to each. If the determinant of $K$ is trivial, we show that any two such surfaces are isotopic, rel. boundary, again provided that they have non-extremal normal Euler number, or that $h$ is $1$, $2$, or $3$.
title Unknotting nonorientable surfaces
topic Geometric Topology
57K40, 57N35, 57R67
url https://arxiv.org/abs/2306.12305