d-Fold Partition Diamonds

Fuente: arXiv
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Auteurs principaux: Dockery, Dalen, Jameson, Marie, Sellers, James A., Wilson, Samuel
Format: Preprint
Publié: 2023
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author Dockery, Dalen
Jameson, Marie
Sellers, James A.
Wilson, Samuel
author_facet Dockery, Dalen
Jameson, Marie
Sellers, James A.
Wilson, Samuel
contents In this work we introduce new combinatorial objects called $d$--fold partition diamonds, which generalize both the classical partition function and the partition diamonds of Andrews, Paule and Riese, and we set $r_d(n)$ to be their counting function. We also consider the Schmidt type $d$--fold partition diamonds, which have counting function $s_d(n).$ Using partition analysis, we then find the generating function for both, and connect the generating functions $\sum_{n= 0}^\infty s_d(n)q^n$ to Eulerian polynomials. This allows us to develop elementary proofs of infinitely many Ramanujan--like congruences satisfied by $s_d(n)$ for various values of $d$, including the following family: for all $d\geq 1$ and all $n\geq 0,$ $s_d(2n+1) \equiv 0 \pmod{2^d}.$
format Preprint
id arxiv_https___arxiv_org_abs_2307_02579
institution arXiv
publishDate 2023
record_format arxiv
spellingShingle d-Fold Partition Diamonds
Dockery, Dalen
Jameson, Marie
Sellers, James A.
Wilson, Samuel
Number Theory
Combinatorics
11P82 (primary), 11P83 (secondary)
In this work we introduce new combinatorial objects called $d$--fold partition diamonds, which generalize both the classical partition function and the partition diamonds of Andrews, Paule and Riese, and we set $r_d(n)$ to be their counting function. We also consider the Schmidt type $d$--fold partition diamonds, which have counting function $s_d(n).$ Using partition analysis, we then find the generating function for both, and connect the generating functions $\sum_{n= 0}^\infty s_d(n)q^n$ to Eulerian polynomials. This allows us to develop elementary proofs of infinitely many Ramanujan--like congruences satisfied by $s_d(n)$ for various values of $d$, including the following family: for all $d\geq 1$ and all $n\geq 0,$ $s_d(2n+1) \equiv 0 \pmod{2^d}.$
title d-Fold Partition Diamonds
topic Number Theory
Combinatorics
11P82 (primary), 11P83 (secondary)
url https://arxiv.org/abs/2307.02579