Lifting all elements in $\mathrm{SL}_n(\mathbb{Z}/q\mathbb{Z})$

Fuente: arXiv
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Main Authors: Kamber, Amitay, Varjú, Péter P.
Format: Preprint
Published: 2023
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author Kamber, Amitay
Varjú, Péter P.
author_facet Kamber, Amitay
Varjú, Péter P.
contents We show that every element of $\mathrm{SL}_{n}(\mathbb{Z}/q\mathbb{Z})$ can be lifted to an element of $\mathrm{SL}_{n}(\mathbb{Z})$ of norm at most $Cq^2\log q$, while there exists an element such that every lift of it is of norm at least $q^{2+o(1)}$. This should be compared to the recent result that almost every element has a lift of norm bounded by $q^{1+1/n+o(1)}$. The main step in the proof is showing that for every $q$, there is a small element in $(\mathbb{Z}/q\mathbb{Z})^\times$ with a large $n$-th root, which is a result of independent interest.
format Preprint
id arxiv_https___arxiv_org_abs_2310_10269
institution arXiv
publishDate 2023
record_format arxiv
spellingShingle Lifting all elements in $\mathrm{SL}_n(\mathbb{Z}/q\mathbb{Z})$
Kamber, Amitay
Varjú, Péter P.
Number Theory
11F06 (Primary) 11J25, 20H05 (Secondary)
We show that every element of $\mathrm{SL}_{n}(\mathbb{Z}/q\mathbb{Z})$ can be lifted to an element of $\mathrm{SL}_{n}(\mathbb{Z})$ of norm at most $Cq^2\log q$, while there exists an element such that every lift of it is of norm at least $q^{2+o(1)}$. This should be compared to the recent result that almost every element has a lift of norm bounded by $q^{1+1/n+o(1)}$. The main step in the proof is showing that for every $q$, there is a small element in $(\mathbb{Z}/q\mathbb{Z})^\times$ with a large $n$-th root, which is a result of independent interest.
title Lifting all elements in $\mathrm{SL}_n(\mathbb{Z}/q\mathbb{Z})$
topic Number Theory
11F06 (Primary) 11J25, 20H05 (Secondary)
url https://arxiv.org/abs/2310.10269