Benford's Law in the ring $\mathbb{Z}(\sqrt{D})$

Fuente: arXiv
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Auteurs principaux: Patterson, Christine, Scheepers, Marion
Format: Preprint
Publié: 2024
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author Patterson, Christine
Scheepers, Marion
author_facet Patterson, Christine
Scheepers, Marion
contents For $D$ a natural number that is not a perfect square and for $k$ a non-zero integer, consider the subset $\mathbb{Z}_k(\sqrt{D})$ of the quadratic integer ring $\mathbb{Z}(\sqrt{D})$ consisting of elements $x+y\sqrt{D}$ for which $x^2 - Dy^2 = k$ . For each $k$ such that the set $\mathbb{Z}_k(\sqrt{D})$ is nonempty, $\mathbb{Z}_k(\sqrt{D})$ has a natural arrangement into a sequence for which the corresponding sequence of integers $x$, as well as the corresponding sequence of integers $y$, are strong Benford sequences.
format Preprint
id arxiv_https___arxiv_org_abs_2402_10864
institution arXiv
publishDate 2024
record_format arxiv
spellingShingle Benford's Law in the ring $\mathbb{Z}(\sqrt{D})$
Patterson, Christine
Scheepers, Marion
Number Theory
Primary 11D09, 11B05, 11B99, Secondary 62R01, 11A55
For $D$ a natural number that is not a perfect square and for $k$ a non-zero integer, consider the subset $\mathbb{Z}_k(\sqrt{D})$ of the quadratic integer ring $\mathbb{Z}(\sqrt{D})$ consisting of elements $x+y\sqrt{D}$ for which $x^2 - Dy^2 = k$ . For each $k$ such that the set $\mathbb{Z}_k(\sqrt{D})$ is nonempty, $\mathbb{Z}_k(\sqrt{D})$ has a natural arrangement into a sequence for which the corresponding sequence of integers $x$, as well as the corresponding sequence of integers $y$, are strong Benford sequences.
title Benford's Law in the ring $\mathbb{Z}(\sqrt{D})$
topic Number Theory
Primary 11D09, 11B05, 11B99, Secondary 62R01, 11A55
url https://arxiv.org/abs/2402.10864