Gespeichert in:
| Hauptverfasser: | , , , , |
|---|---|
| Format: | Preprint |
| Veröffentlicht: |
2024
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| Schlagworte: | |
| Online-Zugang: | https://arxiv.org/abs/2402.19008 |
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Inhaltsangabe:
- Background: Nuclear deformation provides a crucial characteristic of nuclear structure. Conventionally, the quadrupole deformation length of a nucleus, $δ_{2}$, has often been determined based on a macroscopic model through a deformed nuclear potential with the deformation length $δ^{\rm (pot)}_{2}$, which is determined to reproduce the nuclear scattering data. This approach assumes $δ_{2}=δ^{\rm (pot)}_{2}$ although there is no theoretical foundation. Purpose: We clarify the relationship between $δ_{2}$ and $δ^{\rm (pot)}_{2}$ for high-energy heavy-ion scattering systematically to evaluate the validity of the conventional approach to determine the nuclear deformation. Method: The deformation lengths for the $^{12}$C inelastic scattering by $^{12}$C, $^{16}$O, $^{40}$Ca, and $^{208}$Pb targets at $E/A$ = 50--400 MeV are examined. First, we perform microscopic coupled-channel (CC) calculations to relate $δ_{2}$ of the deformed density into the inelastic scattering cross section. Second, we use the deformed potential model to determine $δ^{\rm (pot)}_{2}$ so as to reproduce the microscopic CC result. We then compare $δ^{\rm (pot)}_{2}$ with $δ_{2}$. Results: We find that $δ^{\rm (pot)}_{2}$ is about 20--40 \% smaller than presumed $δ_{2}$, showing strong energy and target dependence. Further analysis, which considers higher-order deformation effects beyond the derivative model, reveals that $δ^{\rm (pot)}_{2}$ is still about 15--35 \% smaller than $δ_{2}$. Conclusion: Our results suggest that one needs to be careful when the deformed potential model for the high-energy heavy-ion scattering is used to extract the nuclear deformation. The conventional approach may underestimate the deformation length $δ_2$ systematically.