Analogue of the Cauchy-Schwarz inequality for determinants: a simple proof

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Main Author: Sidi, Avram
Format: Preprint
Published: 2024
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author Sidi, Avram
author_facet Sidi, Avram
contents In this note, we present a simple proof of an analogue of the Cauchy-Schwarz inequality relevant to products of determinants. Specifically, we show that $$ |\det(A^*MB)|^2\leq \det(A^*MA)\cdot \det(B^*MB),\quad A,B\in \mathbb{C}^{m\times n},$$ where $M\in\mathbb{C}^{m\times m}$ is hermitian positive definite. Here $m$ and $n$ are arbitrary. In case $m\leq n$, equality holds trivially. Equality holds when $m>n$ and $\text{rank}(A)=\text{rank}(B)=n$ if and only if the columns of $A$ and the columns of $B$ span the same subspace of $\mathbb{C}^m$.
format Preprint
id arxiv_https___arxiv_org_abs_2403_19691
institution arXiv
publishDate 2024
record_format arxiv
spellingShingle Analogue of the Cauchy-Schwarz inequality for determinants: a simple proof
Sidi, Avram
General Mathematics
15
In this note, we present a simple proof of an analogue of the Cauchy-Schwarz inequality relevant to products of determinants. Specifically, we show that $$ |\det(A^*MB)|^2\leq \det(A^*MA)\cdot \det(B^*MB),\quad A,B\in \mathbb{C}^{m\times n},$$ where $M\in\mathbb{C}^{m\times m}$ is hermitian positive definite. Here $m$ and $n$ are arbitrary. In case $m\leq n$, equality holds trivially. Equality holds when $m>n$ and $\text{rank}(A)=\text{rank}(B)=n$ if and only if the columns of $A$ and the columns of $B$ span the same subspace of $\mathbb{C}^m$.
title Analogue of the Cauchy-Schwarz inequality for determinants: a simple proof
topic General Mathematics
15
url https://arxiv.org/abs/2403.19691