Comparing Hilbert depth of $I$ with Hilbert depth of $S/I$. II
Fuente:
arXiv
Guardado en:
| Autores principales: | , |
|---|---|
| Formato: | Preprint |
| Publicado: |
2024
|
| Materias: | |
| Acceso en línea: | |
| Etiquetas: |
Agregar Etiqueta
Sin Etiquetas, Sea el primero en etiquetar este registro!
|
| _version_ | 1866914743393976320 |
|---|---|
| author | Bordianu, Andreea I. Cimpoeas, Mircea |
| author_facet | Bordianu, Andreea I. Cimpoeas, Mircea |
| contents | Let $I$ be a squarefree monomial ideal of $S=K[x_1,\ldots,x_n]$. We prove that if $\operatorname{hdepth}(S/I)\leq 6$ of $n\leq 9$ then $\operatorname{hdepth}(I)\geq \operatorname{hdepth}(S/I)$, giving a positive answer to a problem putted in arxiv:2403.17078 |
| format | Preprint |
| id |
arxiv_https___arxiv_org_abs_2404_04646 |
| institution | arXiv |
| publishDate | 2024 |
| record_format | arxiv |
| spellingShingle | Comparing Hilbert depth of $I$ with Hilbert depth of $S/I$. II Bordianu, Andreea I. Cimpoeas, Mircea Commutative Algebra Combinatorics 05A18, 06A07, 13C15, 13P10, 13F20 Let $I$ be a squarefree monomial ideal of $S=K[x_1,\ldots,x_n]$. We prove that if $\operatorname{hdepth}(S/I)\leq 6$ of $n\leq 9$ then $\operatorname{hdepth}(I)\geq \operatorname{hdepth}(S/I)$, giving a positive answer to a problem putted in arxiv:2403.17078 |
| title | Comparing Hilbert depth of $I$ with Hilbert depth of $S/I$. II |
| topic | Commutative Algebra Combinatorics 05A18, 06A07, 13C15, 13P10, 13F20 |
| url | https://arxiv.org/abs/2404.04646 |