On free bases of Banach spaces

Fuente: arXiv
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Autores principales: Pernecká, E., Spěvák, J.
Formato: Preprint
Publicado: 2024
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author Pernecká, E.
Spěvák, J.
author_facet Pernecká, E.
Spěvák, J.
contents We call a closed subset M of a Banach space X a free basis of X if it contains the null vector and every Lipschitz map from M to a Banach space Y, which preserves the null vectors can be uniquely extended to a bounded linear map from X to Y. We then say that two complete metric spaces M and N are Mol-equivalent if they admit bi-Lipschitz copies M' and N', respectively that are free bases of a common Banach space satisfying span M'=span N'. In this note, we compare Mol-equivalence with some other natural equivalences on the class of complete metric spaces. The main result states that Mol-equivalent spaces must have the same Čech-Lebesgue covering dimension. In combination with the work of Godard, this implies that two complete metric spaces with isomorphic Lipschitz-free spaces need not be Mol-equivalent. Also, there exist non-homeomorphic Mol-equivalent metric spaces, and, in contrast with the covering dimension, the metric Assouad dimension is not preserved by Mol-equivalence.
format Preprint
id arxiv_https___arxiv_org_abs_2405_03556
institution arXiv
publishDate 2024
record_format arxiv
spellingShingle On free bases of Banach spaces
Pernecká, E.
Spěvák, J.
Functional Analysis
General Topology
46B03, 54E35, 54F45
We call a closed subset M of a Banach space X a free basis of X if it contains the null vector and every Lipschitz map from M to a Banach space Y, which preserves the null vectors can be uniquely extended to a bounded linear map from X to Y. We then say that two complete metric spaces M and N are Mol-equivalent if they admit bi-Lipschitz copies M' and N', respectively that are free bases of a common Banach space satisfying span M'=span N'. In this note, we compare Mol-equivalence with some other natural equivalences on the class of complete metric spaces. The main result states that Mol-equivalent spaces must have the same Čech-Lebesgue covering dimension. In combination with the work of Godard, this implies that two complete metric spaces with isomorphic Lipschitz-free spaces need not be Mol-equivalent. Also, there exist non-homeomorphic Mol-equivalent metric spaces, and, in contrast with the covering dimension, the metric Assouad dimension is not preserved by Mol-equivalence.
title On free bases of Banach spaces
topic Functional Analysis
General Topology
46B03, 54E35, 54F45
url https://arxiv.org/abs/2405.03556