Exact values of generic subrank

Fuente: arXiv
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Auteurs principaux: Pielasa, Paweł, Šafránek, Matouš, Shatsila, Anatoli
Format: Preprint
Publié: 2024
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author Pielasa, Paweł
Šafránek, Matouš
Shatsila, Anatoli
author_facet Pielasa, Paweł
Šafránek, Matouš
Shatsila, Anatoli
contents In this article we prove the subrank of a generic tensor in $\mathbb{C}^{n,n,n}$ to be $Q(n) = \lfloor\sqrt{3n - 2}\rfloor$ by providing a lower bound to the known upper bound. More generally, we find the generic subrank of tensors of all orders and dimensions. This answers two open questions posed in arXiv:2205.15168v2. Finally, we compute dimensions of varieties of tensors of subrank at least $r$.
format Preprint
id arxiv_https___arxiv_org_abs_2408_07550
institution arXiv
publishDate 2024
record_format arxiv
spellingShingle Exact values of generic subrank
Pielasa, Paweł
Šafránek, Matouš
Shatsila, Anatoli
Algebraic Geometry
Computational Complexity
15A69, 68Q17, 14N07
In this article we prove the subrank of a generic tensor in $\mathbb{C}^{n,n,n}$ to be $Q(n) = \lfloor\sqrt{3n - 2}\rfloor$ by providing a lower bound to the known upper bound. More generally, we find the generic subrank of tensors of all orders and dimensions. This answers two open questions posed in arXiv:2205.15168v2. Finally, we compute dimensions of varieties of tensors of subrank at least $r$.
title Exact values of generic subrank
topic Algebraic Geometry
Computational Complexity
15A69, 68Q17, 14N07
url https://arxiv.org/abs/2408.07550