An Arad and Fisman's theorem on products of conjugacy classes revisited

Fuente: arXiv
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Autori principali: Beltrán, Antonio, Felipe, María José, Melchor, Carmen
Natura: Preprint
Pubblicazione: 2024
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author Beltrán, Antonio
Felipe, María José
Melchor, Carmen
author_facet Beltrán, Antonio
Felipe, María José
Melchor, Carmen
contents A theorem of Z. Arad and E. Fisman establishes that if $A$ and $B$ are two conjugacy classes of a finite group $G$ such that either $AB=A\cup B$ or $AB=A^{-1} \cup B$, then $G$ cannot be non-abelian simple. We demonstrate that, in fact, $\langle A\rangle = \langle B\rangle$ is solvable, the elements of $A$ and $B$ are $p$-elements for some prime $p$, and $\langle A\rangle $ is $p$-nilpotent. Moreover, under the second assumption, it turns out that $A=B$ and this is the only possible case. This research is done by appealing to recently developed techniques and results that are based on the Classification of Finite Simple Groups.
format Preprint
id arxiv_https___arxiv_org_abs_2410_02393
institution arXiv
publishDate 2024
record_format arxiv
spellingShingle An Arad and Fisman's theorem on products of conjugacy classes revisited
Beltrán, Antonio
Felipe, María José
Melchor, Carmen
Group Theory
A theorem of Z. Arad and E. Fisman establishes that if $A$ and $B$ are two conjugacy classes of a finite group $G$ such that either $AB=A\cup B$ or $AB=A^{-1} \cup B$, then $G$ cannot be non-abelian simple. We demonstrate that, in fact, $\langle A\rangle = \langle B\rangle$ is solvable, the elements of $A$ and $B$ are $p$-elements for some prime $p$, and $\langle A\rangle $ is $p$-nilpotent. Moreover, under the second assumption, it turns out that $A=B$ and this is the only possible case. This research is done by appealing to recently developed techniques and results that are based on the Classification of Finite Simple Groups.
title An Arad and Fisman's theorem on products of conjugacy classes revisited
topic Group Theory
url https://arxiv.org/abs/2410.02393