A partial converse to the Riemann--Lebesgue lemma for Bessel--Fourier series of order zero

Fuente: arXiv
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Autor principal: Babb, Ryan L. Acosta
Formato: Preprint
Publicado: 2024
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author Babb, Ryan L. Acosta
author_facet Babb, Ryan L. Acosta
contents It is known that the Bessel--Fourier coefficients $f_m$ of a function $f$ such that $\sqrt{x}f(x)$ is integrable over $[0,1]$ satisfy $f_m/\sqrt{m}\to 0$. We show a partial converse, namely that for $0\leq α<1/2$ and any non-negative $a_m\to 0$, there is a function $f$ such that $x^{α+1}f(x)$ is integrable and its Bessel--Fourier coefficients $f_m$ satisfy $m^{-α}f_m\geq a_m$ and $m^{-α}f_m\to 0$. We conjecture that the same should be true when $α=\frac{1}{2}$, and discuss some consequences of this conjecture.
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id arxiv_https___arxiv_org_abs_2410_17681
institution arXiv
publishDate 2024
record_format arxiv
spellingShingle A partial converse to the Riemann--Lebesgue lemma for Bessel--Fourier series of order zero
Babb, Ryan L. Acosta
Classical Analysis and ODEs
33C10 (Primary), 42A16, 41A30 (Secondary)
It is known that the Bessel--Fourier coefficients $f_m$ of a function $f$ such that $\sqrt{x}f(x)$ is integrable over $[0,1]$ satisfy $f_m/\sqrt{m}\to 0$. We show a partial converse, namely that for $0\leq α<1/2$ and any non-negative $a_m\to 0$, there is a function $f$ such that $x^{α+1}f(x)$ is integrable and its Bessel--Fourier coefficients $f_m$ satisfy $m^{-α}f_m\geq a_m$ and $m^{-α}f_m\to 0$. We conjecture that the same should be true when $α=\frac{1}{2}$, and discuss some consequences of this conjecture.
title A partial converse to the Riemann--Lebesgue lemma for Bessel--Fourier series of order zero
topic Classical Analysis and ODEs
33C10 (Primary), 42A16, 41A30 (Secondary)
url https://arxiv.org/abs/2410.17681