Bijections for faces of braid-type arrangements

Fuente: arXiv
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Autore principale: Bernardi, Olivier
Natura: Preprint
Pubblicazione: 2025
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author Bernardi, Olivier
author_facet Bernardi, Olivier
contents We establish a general bijective framework for encoding faces of some classical hyperplane arrangements. Precisely, we consider hyperplane arrangements in $\mathbb{R}^n$ whose hyperplanes are all of the form $\{x_i-x_j=s\}$ for some $i,j\in[n]$ and $s\in \mathbb{Z}$. Such an arrangement $A$ is \emph{strongly transitive} if it satisfies the following condition: if $\{x_i-x_j=s\}\notin A$ and $\{x_j-x_k=t\}\notin A$ for some $i,j,k\in [n]$ and $s,t\geq 0$, then $\{x_i-x_k=s+t\}\notin A$. For any strongly transitive arrangement $A$, we establish a bijection between the faces of $A$ and some set of decorated plane trees.
format Preprint
id arxiv_https___arxiv_org_abs_2503_00662
institution arXiv
publishDate 2025
record_format arxiv
spellingShingle Bijections for faces of braid-type arrangements
Bernardi, Olivier
Combinatorics
We establish a general bijective framework for encoding faces of some classical hyperplane arrangements. Precisely, we consider hyperplane arrangements in $\mathbb{R}^n$ whose hyperplanes are all of the form $\{x_i-x_j=s\}$ for some $i,j\in[n]$ and $s\in \mathbb{Z}$. Such an arrangement $A$ is \emph{strongly transitive} if it satisfies the following condition: if $\{x_i-x_j=s\}\notin A$ and $\{x_j-x_k=t\}\notin A$ for some $i,j,k\in [n]$ and $s,t\geq 0$, then $\{x_i-x_k=s+t\}\notin A$. For any strongly transitive arrangement $A$, we establish a bijection between the faces of $A$ and some set of decorated plane trees.
title Bijections for faces of braid-type arrangements
topic Combinatorics
url https://arxiv.org/abs/2503.00662