Exploring the Relationships Between the Divisors of Friends of $10$
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arXiv
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| Format: | Preprint |
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2025
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| _version_ | 1866909578040442880 |
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| author | Mandal, Sagar |
| author_facet | Mandal, Sagar |
| contents | A solitary number is a positive integer that shares its abundancy index only with itself. $10$ is the smallest positive integer suspected to be solitary, but no proof has been established so far. In this paper, we prove that not all half of the exponents of the prime divisors of a friend of 10 are congruent to $1$ modulo $3$. Furthermore, we prove that if $F=5^{2a}\cdot Q^2$ ($Q$ is an odd positive integer coprime to $15$) is a friend of $10$, then $σ(5^{2a})+σ(Q^2)$ is congruent to $6$ modulo $8$ if and only if $a$ is even, and $σ(5^{2a}) + σ(Q^2)$ is congruent to $2$ modulo $8$ if and only if $a$ is odd. In addition, if we set $Q={\displaystyle \prod_{i=2}^{ω(F)}}p_{i}^{a_i}$ and $a=a_1$, where $p_i$ are prime numbers, then we establish that $$F>\frac{25}{81}\cdot\prod_{i=1}^{ω(F)}(2a_i + 1)^2,$$ in particular $F> 625\cdot 9^{ω(F)-3}.$ |
| format | Preprint |
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arxiv_https___arxiv_org_abs_2504_08295 |
| institution | arXiv |
| publishDate | 2025 |
| record_format | arxiv |
| spellingShingle | Exploring the Relationships Between the Divisors of Friends of $10$ Mandal, Sagar General Mathematics 11A25 A solitary number is a positive integer that shares its abundancy index only with itself. $10$ is the smallest positive integer suspected to be solitary, but no proof has been established so far. In this paper, we prove that not all half of the exponents of the prime divisors of a friend of 10 are congruent to $1$ modulo $3$. Furthermore, we prove that if $F=5^{2a}\cdot Q^2$ ($Q$ is an odd positive integer coprime to $15$) is a friend of $10$, then $σ(5^{2a})+σ(Q^2)$ is congruent to $6$ modulo $8$ if and only if $a$ is even, and $σ(5^{2a}) + σ(Q^2)$ is congruent to $2$ modulo $8$ if and only if $a$ is odd. In addition, if we set $Q={\displaystyle \prod_{i=2}^{ω(F)}}p_{i}^{a_i}$ and $a=a_1$, where $p_i$ are prime numbers, then we establish that $$F>\frac{25}{81}\cdot\prod_{i=1}^{ω(F)}(2a_i + 1)^2,$$ in particular $F> 625\cdot 9^{ω(F)-3}.$ |
| title | Exploring the Relationships Between the Divisors of Friends of $10$ |
| topic | General Mathematics 11A25 |
| url | https://arxiv.org/abs/2504.08295 |