The algebraic difference of a Cantor set and its complement

Fuente: arXiv
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Auteurs principaux: Nowakowski, Piotr, Pan, Cheng-Han
Format: Preprint
Publié: 2025
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author Nowakowski, Piotr
Pan, Cheng-Han
author_facet Nowakowski, Piotr
Pan, Cheng-Han
contents Let $\mathcal{C}\subseteq[0,1]$ be a Cantor set. In the classical $\mathcal{C}\pm\mathcal{C}$ problems, modifying the ``size'' of $\mathcal{C}$ has a magnified effect on $\mathcal{C}\pm\mathcal{C}$. However, any gain in $\mathcal{C}$ necessarily results in a loss in $\mathcal{C}^c$, and vice versa. This interplay between $\mathcal{C}$ and its complement $\mathcal{C}^c$ raises interesting questions about the delicate balance between the two, particularly in how it influences the ``size'' of $\mathcal{C}^c-\mathcal{C}$. One of our main results indicates that the Lebesgue measure of $\mathcal{C}^c-\mathcal{C}$ has a greatest lower bound of $\frac{3}{2}$.
format Preprint
id arxiv_https___arxiv_org_abs_2505_03170
institution arXiv
publishDate 2025
record_format arxiv
spellingShingle The algebraic difference of a Cantor set and its complement
Nowakowski, Piotr
Pan, Cheng-Han
Classical Analysis and ODEs
28A05, 28A80
Let $\mathcal{C}\subseteq[0,1]$ be a Cantor set. In the classical $\mathcal{C}\pm\mathcal{C}$ problems, modifying the ``size'' of $\mathcal{C}$ has a magnified effect on $\mathcal{C}\pm\mathcal{C}$. However, any gain in $\mathcal{C}$ necessarily results in a loss in $\mathcal{C}^c$, and vice versa. This interplay between $\mathcal{C}$ and its complement $\mathcal{C}^c$ raises interesting questions about the delicate balance between the two, particularly in how it influences the ``size'' of $\mathcal{C}^c-\mathcal{C}$. One of our main results indicates that the Lebesgue measure of $\mathcal{C}^c-\mathcal{C}$ has a greatest lower bound of $\frac{3}{2}$.
title The algebraic difference of a Cantor set and its complement
topic Classical Analysis and ODEs
28A05, 28A80
url https://arxiv.org/abs/2505.03170