New series involving binomial coefficients (III)

Fuente: arXiv
Saved in:
Bibliographic Details
Main Author: Sun, Zhi-Wei
Format: Preprint
Published: 2025
Subjects:
Online Access:
Tags: Add Tag
No Tags, Be the first to tag this record!
_version_ 1866910017127448576
author Sun, Zhi-Wei
author_facet Sun, Zhi-Wei
contents We evaluate some series with summands involving a single binomial coefficient $\binom{6k}{3k}$. For example, we prove that $$\sum_{k=0}^\infty\frac{(63k^2+78k+22)8^k}{(2k+1)(6k+1)(6k+5)\binom{6k}{3k}}=\frac{3π}2.$$ Motivated by Galois theory, we introduce the so-called Duality Principle for irrational series of Ramanujan's type or Zeilberger's type, and apply it to find 26 new irrational series identities. For example, we conjecture that \begin{align*}&\sum_{k=1}^\infty\frac{(32(91\sqrt{33}-523))^{k}}{k^3\binom{2k}k^2\binom{3k}k} \left((91\sqrt{33}+891)k-33\sqrt{33}-225\right) \\&\qquad=320\left(\frac{11}3\sqrt{33}L_{-11}(2)-27L_{-3}(2)\right), \end{align*} where $ L_{d}(2)=\sum_{k=1}^\infty\frac{(\frac{d}k)}{k^2}$ for any integer $d\equiv0,1\pmod4$ with $(\frac{d}k)$ the Kronecker symbol.
format Preprint
id arxiv_https___arxiv_org_abs_2506_01870
institution arXiv
publishDate 2025
record_format arxiv
spellingShingle New series involving binomial coefficients (III)
Sun, Zhi-Wei
Number Theory
11B65, 11M06, 05A19, 11R11
We evaluate some series with summands involving a single binomial coefficient $\binom{6k}{3k}$. For example, we prove that $$\sum_{k=0}^\infty\frac{(63k^2+78k+22)8^k}{(2k+1)(6k+1)(6k+5)\binom{6k}{3k}}=\frac{3π}2.$$ Motivated by Galois theory, we introduce the so-called Duality Principle for irrational series of Ramanujan's type or Zeilberger's type, and apply it to find 26 new irrational series identities. For example, we conjecture that \begin{align*}&\sum_{k=1}^\infty\frac{(32(91\sqrt{33}-523))^{k}}{k^3\binom{2k}k^2\binom{3k}k} \left((91\sqrt{33}+891)k-33\sqrt{33}-225\right) \\&\qquad=320\left(\frac{11}3\sqrt{33}L_{-11}(2)-27L_{-3}(2)\right), \end{align*} where $ L_{d}(2)=\sum_{k=1}^\infty\frac{(\frac{d}k)}{k^2}$ for any integer $d\equiv0,1\pmod4$ with $(\frac{d}k)$ the Kronecker symbol.
title New series involving binomial coefficients (III)
topic Number Theory
11B65, 11M06, 05A19, 11R11
url https://arxiv.org/abs/2506.01870