Once again on an analogue of the certain Voevodsky theorem
Fuente:
arXiv
Saved in:
| Main Authors: | , |
|---|---|
| Format: | Preprint |
| Published: |
2025
|
| Subjects: | |
| Online Access: | |
| Tags: |
Add Tag
No Tags, Be the first to tag this record!
|
| _version_ | 1866913884730818560 |
|---|---|
| author | Panin, Ivan Tyurin, Dimitrii |
| author_facet | Panin, Ivan Tyurin, Dimitrii |
| contents | Suppose that $F$ is an $\mathbb{A}^{1}$-invariant quasi-stable $\mathbb{Z}F_{\ast}$-presheaf. Then its Zariski sheafification $F_{Zar}$ coincides with its Nisnevich sheafification $F_{Nis}$. Moreover, if $X\in Sm/k$ is $k$-smooth, then for any $n$ there is equality $H^{n}_{Zar}(X, F_{Zar})=H^{n}_{Nis}(X,F_{Nis})$. |
| format | Preprint |
| id |
arxiv_https___arxiv_org_abs_2506_06795 |
| institution | arXiv |
| publishDate | 2025 |
| record_format | arxiv |
| spellingShingle | Once again on an analogue of the certain Voevodsky theorem Panin, Ivan Tyurin, Dimitrii K-Theory and Homology Suppose that $F$ is an $\mathbb{A}^{1}$-invariant quasi-stable $\mathbb{Z}F_{\ast}$-presheaf. Then its Zariski sheafification $F_{Zar}$ coincides with its Nisnevich sheafification $F_{Nis}$. Moreover, if $X\in Sm/k$ is $k$-smooth, then for any $n$ there is equality $H^{n}_{Zar}(X, F_{Zar})=H^{n}_{Nis}(X,F_{Nis})$. |
| title | Once again on an analogue of the certain Voevodsky theorem |
| topic | K-Theory and Homology |
| url | https://arxiv.org/abs/2506.06795 |