The longest increasing subsequence of Brownian separable permutons
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arXiv
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| Format: | Preprint |
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2025
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| _version_ | 1866918068981071872 |
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| author | Adhikari, Arka Borga, Jacopo Budzinski, Thomas Da Silva, William Sénizergues, Delphin |
| author_facet | Adhikari, Arka Borga, Jacopo Budzinski, Thomas Da Silva, William Sénizergues, Delphin |
| contents | We establish a scaling limit result for the length $\operatorname{LIS}(σ_n)$ of the longest increasing subsequence of a permutation $σ_n$ of size $n$ sampled from the Brownian separable permuton $\boldsymbolμ_p$ of parameter $p\in(0,1)$, which is the universal limit of pattern-avoiding permutations. Specifically, we prove that \[\frac{\operatorname{LIS}(σ_n)}{n^α}\;\underset{n\to\infty}{\overset{\mathrm{a.s.}}{\longrightarrow}}\; X,\] where $α=α(p)$ is the unique solution in the interval $(1/2,1)$ to the equation \[\frac{1}{4^{\frac{1}{2α}}\sqrtπ}\,\frac{Γ\big(\tfrac{1}{2}-\tfrac{1}{2α}\big)}{Γ\big(1-\tfrac{1}{2α}\big)}=\frac{p}{p-1},\] and $X=X(p)$ is a non-deterministic and a.s. positive and finite random variable, which is a measurable function of the Brownian separable permuton. Notably, the exponent $α(p)$ is an increasing continuous function of $p$ with $α(0^+)=1/2$, $α(1^-)=1$ and $α(1/2)\approx0.815226$, which corresponds to the permuton limit of uniform separable permutations. We prove analogous results for the size of the largest clique of a graph sampled from the Brownian cographon of parameter $p\in(0,1)$. |
| format | Preprint |
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arxiv_https___arxiv_org_abs_2506_19123 |
| institution | arXiv |
| publishDate | 2025 |
| record_format | arxiv |
| spellingShingle | The longest increasing subsequence of Brownian separable permutons Adhikari, Arka Borga, Jacopo Budzinski, Thomas Da Silva, William Sénizergues, Delphin Probability Combinatorics We establish a scaling limit result for the length $\operatorname{LIS}(σ_n)$ of the longest increasing subsequence of a permutation $σ_n$ of size $n$ sampled from the Brownian separable permuton $\boldsymbolμ_p$ of parameter $p\in(0,1)$, which is the universal limit of pattern-avoiding permutations. Specifically, we prove that \[\frac{\operatorname{LIS}(σ_n)}{n^α}\;\underset{n\to\infty}{\overset{\mathrm{a.s.}}{\longrightarrow}}\; X,\] where $α=α(p)$ is the unique solution in the interval $(1/2,1)$ to the equation \[\frac{1}{4^{\frac{1}{2α}}\sqrtπ}\,\frac{Γ\big(\tfrac{1}{2}-\tfrac{1}{2α}\big)}{Γ\big(1-\tfrac{1}{2α}\big)}=\frac{p}{p-1},\] and $X=X(p)$ is a non-deterministic and a.s. positive and finite random variable, which is a measurable function of the Brownian separable permuton. Notably, the exponent $α(p)$ is an increasing continuous function of $p$ with $α(0^+)=1/2$, $α(1^-)=1$ and $α(1/2)\approx0.815226$, which corresponds to the permuton limit of uniform separable permutations. We prove analogous results for the size of the largest clique of a graph sampled from the Brownian cographon of parameter $p\in(0,1)$. |
| title | The longest increasing subsequence of Brownian separable permutons |
| topic | Probability Combinatorics |
| url | https://arxiv.org/abs/2506.19123 |