A Note on Deaconescu's Conjecture

Fuente: arXiv
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Main Author: Mandal, Sagar
Format: Preprint
Published: 2025
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author Mandal, Sagar
author_facet Mandal, Sagar
contents Hasanalizade [1] studied Deaconescu's conjecture for positive composite integer $n$. A positive composite integer $n\geq4$ is said to be a Deaconescu number if $S_2(n)\mid ϕ(n)-1$. In this paper, we improve Hasanalizade's result by proving that a Deaconescu number $n$ must have at least seventeen distinct prime divisors, i.e., $ω(n)\geq 17$ and must be strictly larger than $5.86\cdot10^{22}$. Further, we prove that if any Deaconescu number $n$ has all prime divisors greater than or equal to $11$, then $ω(n)\geq p^{*}$, where $p^{*}$ is the smallest prime divisor of $n$ and if $n\in D_3$ then all the prime divisors of $n$ must be congruent to $2$ modulo $3$ and $ω(n)\geq 48$.
format Preprint
id arxiv_https___arxiv_org_abs_2507_02930
institution arXiv
publishDate 2025
record_format arxiv
spellingShingle A Note on Deaconescu's Conjecture
Mandal, Sagar
General Mathematics
11A25
Hasanalizade [1] studied Deaconescu's conjecture for positive composite integer $n$. A positive composite integer $n\geq4$ is said to be a Deaconescu number if $S_2(n)\mid ϕ(n)-1$. In this paper, we improve Hasanalizade's result by proving that a Deaconescu number $n$ must have at least seventeen distinct prime divisors, i.e., $ω(n)\geq 17$ and must be strictly larger than $5.86\cdot10^{22}$. Further, we prove that if any Deaconescu number $n$ has all prime divisors greater than or equal to $11$, then $ω(n)\geq p^{*}$, where $p^{*}$ is the smallest prime divisor of $n$ and if $n\in D_3$ then all the prime divisors of $n$ must be congruent to $2$ modulo $3$ and $ω(n)\geq 48$.
title A Note on Deaconescu's Conjecture
topic General Mathematics
11A25
url https://arxiv.org/abs/2507.02930