$q$-Congruences for Z.-W. Sun's generalized polynomials $w^{(α)}_k(x)$
Fuente:
arXiv
Salvato in:
| Autori principali: | , |
|---|---|
| Natura: | Preprint |
| Pubblicazione: |
2025
|
| Soggetti: | |
| Accesso online: | |
| Tags: |
Aggiungi Tag
Nessun Tag, puoi essere il primo ad aggiungerne!!
|
| _version_ | 1866912468714913792 |
|---|---|
| author | Li, Lin-Yue Wang, Rong-Hua |
| author_facet | Li, Lin-Yue Wang, Rong-Hua |
| contents | In 2022, Z.-W. Sun defined \begin{equation*} w_k^{(α)}{(x)}=\sum_{j=1}^{k}w(k,j)^αx^{j-1}, \end{equation*} where $k,α$ are positive integers and $w(k,j)=\frac{1}{j}\binom{k-1}{j-1}\binom{k+j}{j-1}$. Let $(x)_{0}=1$ and $(x)_{n}=x(x+1)\cdots(x+n-1)$ for all $n\geq 1$. In this paper, it is proved by $q$-congruences that for any positive integers ${α,β, m,n,r}$, we have \begin{equation*} \frac{(2,n)}{n(n+1)(n+2)}\sum_{k=1}^{n}k^r(k+1)^r(2k+1)w_{k}^{(α)}(x)^{m}\in\mathbb{Z}[x], \end{equation*} \begin{equation*} \frac{(2,n)}{n(n+1)(n+2)}\sum_{k=1}^{n}(-1)^{k}k^r(k+1)^r(2k+1) w_{k}^{(α)}(x)^{m}\in\mathbb{Z}[x], \end{equation*} and \begin{equation*} \frac{2}{[n,n+1,\cdots,n+2β+1]}\sum_{k=1}^{n}(k)_β^r(k+β+1)_β^r(k+β) \prod_{i=0}^{2β-1}w_{k+i}^{(α)}(x)^m\in\mathbb{Z}[x], \end{equation*} where $[n,n+1,\cdots,n+2β+1]$ is the least common multiple of $n$, $n+1$, $\cdots$, $n+2β+1$. Taking $r=β=1$ above will confirm some of Z.-W. Sun's conjectures. |
| format | Preprint |
| id |
arxiv_https___arxiv_org_abs_2507_04653 |
| institution | arXiv |
| publishDate | 2025 |
| record_format | arxiv |
| spellingShingle | $q$-Congruences for Z.-W. Sun's generalized polynomials $w^{(α)}_k(x)$ Li, Lin-Yue Wang, Rong-Hua Number Theory Combinatorics In 2022, Z.-W. Sun defined \begin{equation*} w_k^{(α)}{(x)}=\sum_{j=1}^{k}w(k,j)^αx^{j-1}, \end{equation*} where $k,α$ are positive integers and $w(k,j)=\frac{1}{j}\binom{k-1}{j-1}\binom{k+j}{j-1}$. Let $(x)_{0}=1$ and $(x)_{n}=x(x+1)\cdots(x+n-1)$ for all $n\geq 1$. In this paper, it is proved by $q$-congruences that for any positive integers ${α,β, m,n,r}$, we have \begin{equation*} \frac{(2,n)}{n(n+1)(n+2)}\sum_{k=1}^{n}k^r(k+1)^r(2k+1)w_{k}^{(α)}(x)^{m}\in\mathbb{Z}[x], \end{equation*} \begin{equation*} \frac{(2,n)}{n(n+1)(n+2)}\sum_{k=1}^{n}(-1)^{k}k^r(k+1)^r(2k+1) w_{k}^{(α)}(x)^{m}\in\mathbb{Z}[x], \end{equation*} and \begin{equation*} \frac{2}{[n,n+1,\cdots,n+2β+1]}\sum_{k=1}^{n}(k)_β^r(k+β+1)_β^r(k+β) \prod_{i=0}^{2β-1}w_{k+i}^{(α)}(x)^m\in\mathbb{Z}[x], \end{equation*} where $[n,n+1,\cdots,n+2β+1]$ is the least common multiple of $n$, $n+1$, $\cdots$, $n+2β+1$. Taking $r=β=1$ above will confirm some of Z.-W. Sun's conjectures. |
| title | $q$-Congruences for Z.-W. Sun's generalized polynomials $w^{(α)}_k(x)$ |
| topic | Number Theory Combinatorics |
| url | https://arxiv.org/abs/2507.04653 |