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Main Author: Djament, Aurélien
Format: Preprint
Published: 2025
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Online Access:https://arxiv.org/abs/2507.13047
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author Djament, Aurélien
author_facet Djament, Aurélien
contents If $K$ is a field with enough roots of unity and $V$ an abelian group, the $K$-algebra $K[V]$ of the group $V$ is split semisimple, so that the canonical morphism $K[V]\to K^{V^\sharp}$, where $V^\sharp$ denotes the dual group of $V$ (which may be seen as Hom$(V,K^\times)$), is an isomorphism of $K$-algebras. If one removes the assumption that $K$ has enough roots of unity, one can easily deduce from it (by using a base change and Krull-Schmidt) that it remains a $K$-linear isomorphism $K[V]\xrightarrow{\simeq} K^{V^\sharp}$ natural in the group $V$ if one restricts to finite groups $V$ canceled by a fixed nonzero integer. The question of whether such an isomorphism, natural in the abelian group $V$, still exists without any other restriction than $V$ is finite and its order is invertible in $K$, is less obvious; we solve it positively, in a somewhat more general setting ($K$ being any commutative ring), by using Gauss sums. We also explore some related functorial questions.
format Preprint
id arxiv_https___arxiv_org_abs_2507_13047
institution arXiv
publishDate 2025
record_format arxiv
spellingShingle Note on the linearisation of finite abelian groups
Djament, Aurélien
Category Theory
Group Theory
If $K$ is a field with enough roots of unity and $V$ an abelian group, the $K$-algebra $K[V]$ of the group $V$ is split semisimple, so that the canonical morphism $K[V]\to K^{V^\sharp}$, where $V^\sharp$ denotes the dual group of $V$ (which may be seen as Hom$(V,K^\times)$), is an isomorphism of $K$-algebras. If one removes the assumption that $K$ has enough roots of unity, one can easily deduce from it (by using a base change and Krull-Schmidt) that it remains a $K$-linear isomorphism $K[V]\xrightarrow{\simeq} K^{V^\sharp}$ natural in the group $V$ if one restricts to finite groups $V$ canceled by a fixed nonzero integer. The question of whether such an isomorphism, natural in the abelian group $V$, still exists without any other restriction than $V$ is finite and its order is invertible in $K$, is less obvious; we solve it positively, in a somewhat more general setting ($K$ being any commutative ring), by using Gauss sums. We also explore some related functorial questions.
title Note on the linearisation of finite abelian groups
topic Category Theory
Group Theory
url https://arxiv.org/abs/2507.13047