Rescaling of unconditional Schauder frames in Hilbert spaces and completely bounded maps

Fuente: arXiv
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Autor principal: Tselishchev, Anton
Formato: Preprint
Publicado: 2025
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author Tselishchev, Anton
author_facet Tselishchev, Anton
contents We prove that if every element $u$ in a Hilbert space $H$ admits a representation as unconditionally convergent series $$u=\sum_{k=1}^\infty \langle u, y_k\rangle x_k,$$ then there exist nonzero scalars $\{α_k\}_{k=1}^\infty$ such that both sequences $\{α_k x_k\}_{k=1}^\infty$ and $\{\overlineα_k^{-1}y_k\}_{k=1}^\infty$ are frames. Our result has the following equivalent reformulation: if $Φ:\ell^\infty\to B(H)$ is a bounded linear map such that for every element of the unit vector basis $e_k$ in $\ell^\infty$ the operator $Φ(e_k)$ has rank one, then $Φ$ is completely bounded.
format Preprint
id arxiv_https___arxiv_org_abs_2508_02802
institution arXiv
publishDate 2025
record_format arxiv
spellingShingle Rescaling of unconditional Schauder frames in Hilbert spaces and completely bounded maps
Tselishchev, Anton
Functional Analysis
Operator Algebras
46B15, 46L07
We prove that if every element $u$ in a Hilbert space $H$ admits a representation as unconditionally convergent series $$u=\sum_{k=1}^\infty \langle u, y_k\rangle x_k,$$ then there exist nonzero scalars $\{α_k\}_{k=1}^\infty$ such that both sequences $\{α_k x_k\}_{k=1}^\infty$ and $\{\overlineα_k^{-1}y_k\}_{k=1}^\infty$ are frames. Our result has the following equivalent reformulation: if $Φ:\ell^\infty\to B(H)$ is a bounded linear map such that for every element of the unit vector basis $e_k$ in $\ell^\infty$ the operator $Φ(e_k)$ has rank one, then $Φ$ is completely bounded.
title Rescaling of unconditional Schauder frames in Hilbert spaces and completely bounded maps
topic Functional Analysis
Operator Algebras
46B15, 46L07
url https://arxiv.org/abs/2508.02802