Hilbert space models and Blaschke frames

Fuente: arXiv
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Main Author: Evans, Connor
Format: Preprint
Published: 2025
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author Evans, Connor
author_facet Evans, Connor
contents For a finite Blaschke product $B$ and for an isometry $V$ on an infinite-dimensional separable complex Hilbert space $\mathcal{H}$ we study a sequence $(b_m)_{m=1}^\infty$ of vectors in $\mathcal{H}$, defined by $b_m = B(V^*)e_m$, where $(e_m)_{m=1}^\infty$ is an orthonormal basis in $\mathcal{H}$. We call $(b_m)_{m=1}^\infty$ a Blaschke frame for $B$ with isometry $V$ on $\mathcal{H}$. We show how instrumental the use of Hilbert space models are in frame theory by completely solving the question of redundancy for a Blaschke frame, that is, what vectors can be removed from the frame $(b_{m})_{m=1}^{\infty}$ such that $(b_{m})_{m\neq k}$ is still a frame? Using the Wold decomposition, we prove that a Blaschke frame can have no redundant vectors (a Riesz basis), have some redundant vectors, or every vector is redundant (a fully insured frame). These unique cases depend on the choice of finite Blaschke product and which isometry one chooses in the construction of a Blaschke frame.
format Preprint
id arxiv_https___arxiv_org_abs_2510_18816
institution arXiv
publishDate 2025
record_format arxiv
spellingShingle Hilbert space models and Blaschke frames
Evans, Connor
Functional Analysis
Complex Variables
46B15 (Primary), 30J10, 42C15, 47A60
For a finite Blaschke product $B$ and for an isometry $V$ on an infinite-dimensional separable complex Hilbert space $\mathcal{H}$ we study a sequence $(b_m)_{m=1}^\infty$ of vectors in $\mathcal{H}$, defined by $b_m = B(V^*)e_m$, where $(e_m)_{m=1}^\infty$ is an orthonormal basis in $\mathcal{H}$. We call $(b_m)_{m=1}^\infty$ a Blaschke frame for $B$ with isometry $V$ on $\mathcal{H}$. We show how instrumental the use of Hilbert space models are in frame theory by completely solving the question of redundancy for a Blaschke frame, that is, what vectors can be removed from the frame $(b_{m})_{m=1}^{\infty}$ such that $(b_{m})_{m\neq k}$ is still a frame? Using the Wold decomposition, we prove that a Blaschke frame can have no redundant vectors (a Riesz basis), have some redundant vectors, or every vector is redundant (a fully insured frame). These unique cases depend on the choice of finite Blaschke product and which isometry one chooses in the construction of a Blaschke frame.
title Hilbert space models and Blaschke frames
topic Functional Analysis
Complex Variables
46B15 (Primary), 30J10, 42C15, 47A60
url https://arxiv.org/abs/2510.18816