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Main Author: Cruz, R. M. de A.
Format: Preprint
Published: 2025
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Online Access:https://arxiv.org/abs/2510.24947
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author Cruz, R. M. de A.
author_facet Cruz, R. M. de A.
contents Let $M$ be the disk or a compact, connected surface without boundary different from the sphere $S^2$ and the real projective plane $\mathbb{R}P^2$, and let $N$ be a compact, connected surface (possibly with boundary). It is known that the pure braid groups $P_n(M)$ of $M$ are bi-orderable, and, for $n\geq 3$, that the full braid groups $B_n(M)$ of $M$ are not bi-orderable. The main purpose of this article is to show that for all $n \geq 3$, any subgroup $H$ of $B_n(N)$ that satisfies $P_n(N) \subsetneq H \subset B_n(N)$ is not bi-orderable.
format Preprint
id arxiv_https___arxiv_org_abs_2510_24947
institution arXiv
publishDate 2025
record_format arxiv
spellingShingle Intermediate subgroups of braid groups are not bi-orderable
Cruz, R. M. de A.
Geometric Topology
Algebraic Topology
20F36, 20F60, 06F15
Let $M$ be the disk or a compact, connected surface without boundary different from the sphere $S^2$ and the real projective plane $\mathbb{R}P^2$, and let $N$ be a compact, connected surface (possibly with boundary). It is known that the pure braid groups $P_n(M)$ of $M$ are bi-orderable, and, for $n\geq 3$, that the full braid groups $B_n(M)$ of $M$ are not bi-orderable. The main purpose of this article is to show that for all $n \geq 3$, any subgroup $H$ of $B_n(N)$ that satisfies $P_n(N) \subsetneq H \subset B_n(N)$ is not bi-orderable.
title Intermediate subgroups of braid groups are not bi-orderable
topic Geometric Topology
Algebraic Topology
20F36, 20F60, 06F15
url https://arxiv.org/abs/2510.24947