Spectrum of normal operators that generate certain scalable iterative systems
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arXiv
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| Format: | Preprint |
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2025
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| _version_ | 1866915626952425472 |
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| author | Yu, Pu-Ting |
| author_facet | Yu, Pu-Ting |
| contents | Let $A\colon H\rightarrow H$ be a normal operator on an infinite-dimensional separable Hilbert space $H$ and let $S\subseteq H$ be a finite subset such that $\{A^nx\}_{n\geq 0,\,x\in S}$ can be rescaled to form a frame for $H$. That is, there exist some subsets $J_x\subseteq \mathbb{N}\cup\{0\}$ and some set of nonzero scalars $(c_{n,x})_{n\in J_x,\,x\in S}$ such that $\{c_{n,x}A^nx\}_{n\in J_x,\,x\in S}$ forms a frame for $H.$ Assume that there exist some $η\in\mathbb{N}$ and $δ>0$ such that for each infinite $J_x$ there is an increasing syndetic subsequence $(n^x_{k})_{k\in \mathbb{N}}\subseteq J_x$ satisfying $|c_{n^x_{k},x}|\|A^{i^x_{k}}x\|\geq δ$ for some non-negative integers $i^x_{k}$ with $|i^x_{k}- n^x_{k}|\leq η$ for all $k\in \mathbb{N}$. We prove that there exist finitely many numbers $(r_i)_{i=1}^N$ such that the continuous spectrum of $A$ is concentrated on arcs of a circle centered at origin with radius $r_i$. In particular, $A$ must be a diagonal operator if $S$ is a singleton.
As an application, we establish the conjecture proposed by Aldroubi et al.\ asserting that the iterative system $\{\frac{A^nx}{\|A^nx\|}\}_{n\geq 0,\,x\in S}$ is never a frame for $H$, provided one of the following two conditions holds: (i) The continuous spectrum of $A$ contains more than $|S|-1$ points with distinct moduli; (ii) $S$ is a singleton and $A$ is not a diagonal operator |
| format | Preprint |
| id |
arxiv_https___arxiv_org_abs_2511_15625 |
| institution | arXiv |
| publishDate | 2025 |
| record_format | arxiv |
| spellingShingle | Spectrum of normal operators that generate certain scalable iterative systems Yu, Pu-Ting Functional Analysis Let $A\colon H\rightarrow H$ be a normal operator on an infinite-dimensional separable Hilbert space $H$ and let $S\subseteq H$ be a finite subset such that $\{A^nx\}_{n\geq 0,\,x\in S}$ can be rescaled to form a frame for $H$. That is, there exist some subsets $J_x\subseteq \mathbb{N}\cup\{0\}$ and some set of nonzero scalars $(c_{n,x})_{n\in J_x,\,x\in S}$ such that $\{c_{n,x}A^nx\}_{n\in J_x,\,x\in S}$ forms a frame for $H.$ Assume that there exist some $η\in\mathbb{N}$ and $δ>0$ such that for each infinite $J_x$ there is an increasing syndetic subsequence $(n^x_{k})_{k\in \mathbb{N}}\subseteq J_x$ satisfying $|c_{n^x_{k},x}|\|A^{i^x_{k}}x\|\geq δ$ for some non-negative integers $i^x_{k}$ with $|i^x_{k}- n^x_{k}|\leq η$ for all $k\in \mathbb{N}$. We prove that there exist finitely many numbers $(r_i)_{i=1}^N$ such that the continuous spectrum of $A$ is concentrated on arcs of a circle centered at origin with radius $r_i$. In particular, $A$ must be a diagonal operator if $S$ is a singleton. As an application, we establish the conjecture proposed by Aldroubi et al.\ asserting that the iterative system $\{\frac{A^nx}{\|A^nx\|}\}_{n\geq 0,\,x\in S}$ is never a frame for $H$, provided one of the following two conditions holds: (i) The continuous spectrum of $A$ contains more than $|S|-1$ points with distinct moduli; (ii) $S$ is a singleton and $A$ is not a diagonal operator |
| title | Spectrum of normal operators that generate certain scalable iterative systems |
| topic | Functional Analysis |
| url | https://arxiv.org/abs/2511.15625 |