More on the sum-product problem for integers with few prime factors

Fuente: arXiv
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Autores principales: Agrawal, Rishika, Bloom, Thomas F., Petridis, Giorgis
Formato: Preprint
Publicado: 2025
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author Agrawal, Rishika
Bloom, Thomas F.
Petridis, Giorgis
author_facet Agrawal, Rishika
Bloom, Thomas F.
Petridis, Giorgis
contents We show that if $A\subset \mathbb{Z}$ is a finite set of integers in which every integer is divisible by $O(1)$ many primes then \[\max(\lvert A+A\rvert,\lvert AA\rvert) \geq \lvert A\rvert^{12/7-o(1)}\] and, for any $m\geq 2$, \[\max(\lvert mA\rvert, \lvert A^{(m)}\rvert) \geq \lvert A\rvert^{\frac{2}{3}m+\frac{1}{3}-o(1)}.\] Finally, we show that if $A\subset \mathbb{Q}$ is a finite set of rationals in which the numerator and denominator of every $x\in A$ is divisible by $O(1)$ many primes then $\lvert A+AA\rvert \geq \lvert A\rvert^{2-o(1)}$.
format Preprint
id arxiv_https___arxiv_org_abs_2512_04931
institution arXiv
publishDate 2025
record_format arxiv
spellingShingle More on the sum-product problem for integers with few prime factors
Agrawal, Rishika
Bloom, Thomas F.
Petridis, Giorgis
Number Theory
We show that if $A\subset \mathbb{Z}$ is a finite set of integers in which every integer is divisible by $O(1)$ many primes then \[\max(\lvert A+A\rvert,\lvert AA\rvert) \geq \lvert A\rvert^{12/7-o(1)}\] and, for any $m\geq 2$, \[\max(\lvert mA\rvert, \lvert A^{(m)}\rvert) \geq \lvert A\rvert^{\frac{2}{3}m+\frac{1}{3}-o(1)}.\] Finally, we show that if $A\subset \mathbb{Q}$ is a finite set of rationals in which the numerator and denominator of every $x\in A$ is divisible by $O(1)$ many primes then $\lvert A+AA\rvert \geq \lvert A\rvert^{2-o(1)}$.
title More on the sum-product problem for integers with few prime factors
topic Number Theory
url https://arxiv.org/abs/2512.04931