A counterexample to a conjecture of Sárközy on sums and products modulo a prime

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Auteur principal: Tang, Quanyu
Format: Preprint
Publié: 2026
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author Tang, Quanyu
author_facet Tang, Quanyu
contents Let $p$ be a prime and, for $A\subseteq \mathbb F_p$, define $A^\ast=(A+A)\cup(AA)$. Sárközy conjectured that there exist constants $c>0$ and $p_0$ such that, for every prime $p>p_0$, every set $A\subseteq \mathbb F_p$ with $|A|>\left(\frac12-c\right)p$ satisfies $\mathbb F_p^\times\subseteq A^\ast$. We disprove this conjecture: for every odd prime $p\ge 5$, there exists a set $A\subseteq \mathbb F_p$ with $|A|=\frac{p-1}{2}$ such that $1\notin A^\ast$. Thus no positive constant $c$ can satisfy Sárközy's conjecture. Conversely, if $|A|>\frac{p}{2}$, then $A+A=\mathbb F_p$. Therefore the sharp threshold is exactly $\frac12$.
format Preprint
id arxiv_https___arxiv_org_abs_2603_29992
institution arXiv
publishDate 2026
record_format arxiv
spellingShingle A counterexample to a conjecture of Sárközy on sums and products modulo a prime
Tang, Quanyu
Number Theory
11B75, 05C69
Let $p$ be a prime and, for $A\subseteq \mathbb F_p$, define $A^\ast=(A+A)\cup(AA)$. Sárközy conjectured that there exist constants $c>0$ and $p_0$ such that, for every prime $p>p_0$, every set $A\subseteq \mathbb F_p$ with $|A|>\left(\frac12-c\right)p$ satisfies $\mathbb F_p^\times\subseteq A^\ast$. We disprove this conjecture: for every odd prime $p\ge 5$, there exists a set $A\subseteq \mathbb F_p$ with $|A|=\frac{p-1}{2}$ such that $1\notin A^\ast$. Thus no positive constant $c$ can satisfy Sárközy's conjecture. Conversely, if $|A|>\frac{p}{2}$, then $A+A=\mathbb F_p$. Therefore the sharp threshold is exactly $\frac12$.
title A counterexample to a conjecture of Sárközy on sums and products modulo a prime
topic Number Theory
11B75, 05C69
url https://arxiv.org/abs/2603.29992