Energy → hbar/delta(t) and Momentum→ hbar/delta(x) from EE = pcpc + momocccc?

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Main Author: Ruggeri, Francesco R.
Format: Recurso digital
Published: Zenodo 2025
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author Ruggeri, Francesco R.
author_facet Ruggeri, Francesco R.
contents <p>      We consider the special relativistic relation EE = pp+momo (hbar=1,c=1) and write it as: E= pv + mocc sqrt(1-vv/cc). As mo-> 0 and v→c at the same time (i.e. the photon case), one has:  E = pc, but at the same time, delta x = c delta t in any frame. This suggests that delta x and delta t are not fixed constants, but change with frame and that E is proportional to 1/delta(t) and p to 1/ delta(x) in the mo->0, v→c limit. </p> <p>   In the mo>0, v<<c case,  delta(x) = v delta(t) + mocc sqrt(1-vv/cc) /constant which does not coincide with delta1(x) = v delta1(t). This begs the question: Why have two sets of measures for x and t? We note that in the photon case, even though there is one set, it is linked with two experimental results. The first is the measurement of speed and the second is two-slit interference. Thus, in the mo>0 case, one may have two sets, one two measure speed and the other interference and there is no reason for these to coincide. Thus, we argue that special relativity actually suggests an intrinsic delta(x) and delta(t) proportional to 1/p and 1/E, which do not transform as a 4-vector.</p> <p> </p>
format Recurso digital
id zenodo_https___doi_org_10_5281_zenodo_15069253
institution Zenodo
language
publishDate 2025
publisher Zenodo
record_format zenodo
spellingShingle Energy → hbar/delta(t) and Momentum→ hbar/delta(x) from EE = pcpc + momocccc?
Ruggeri, Francesco R.
<p>      We consider the special relativistic relation EE = pp+momo (hbar=1,c=1) and write it as: E= pv + mocc sqrt(1-vv/cc). As mo-> 0 and v→c at the same time (i.e. the photon case), one has:  E = pc, but at the same time, delta x = c delta t in any frame. This suggests that delta x and delta t are not fixed constants, but change with frame and that E is proportional to 1/delta(t) and p to 1/ delta(x) in the mo->0, v→c limit. </p> <p>   In the mo>0, v<<c case,  delta(x) = v delta(t) + mocc sqrt(1-vv/cc) /constant which does not coincide with delta1(x) = v delta1(t). This begs the question: Why have two sets of measures for x and t? We note that in the photon case, even though there is one set, it is linked with two experimental results. The first is the measurement of speed and the second is two-slit interference. Thus, in the mo>0 case, one may have two sets, one two measure speed and the other interference and there is no reason for these to coincide. Thus, we argue that special relativity actually suggests an intrinsic delta(x) and delta(t) proportional to 1/p and 1/E, which do not transform as a 4-vector.</p> <p> </p>
title Energy → hbar/delta(t) and Momentum→ hbar/delta(x) from EE = pcpc + momocccc?
url https://doi.org/10.5281/zenodo.15069253