Linear recurrences for S_r(k) in the F_p-root Laurent expansion

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Autore principale: Niedbala Giraudin, David
Natura: Recurso digital
Pubblicazione: Zenodo 2026
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author Niedbala Giraudin, David
author_facet Niedbala Giraudin, David
contents <p>Starting from the closed-form generating functions sum_r T_r(k) z^r = (1-z)^{1/z-k} prod_{m=1}^{k-1}(1-mz), we derive the linear recurrence r S_r(k) = sum_{j=1}^r c_j^{(k)} S_{r-j}(k) with S_0(k) = 1 and coefficients c_j^{(k)} = 1/(j+1) + (k-1) - sum_{m=1}^{k-1} m^j. The identity c_j^{(1)} = c_j^{(2)} = 1/(j+1) yields a fourth, purely algebraic proof of the symmetry S_r(1) = S_r(2). The recurrence is verified in exact rational arithmetic for k in {1, 2, 3, 4, 5} and r in {0, ..., 12} and provides an O(r^2)-time algorithm for computing S_r(k), compared to O(r^3) for the Vandermonde/falling-factorial method.</p>
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id zenodo_https___doi_org_10_5281_zenodo_19700972
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publishDate 2026
publisher Zenodo
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spellingShingle Linear recurrences for S_r(k) in the F_p-root Laurent expansion
Niedbala Giraudin, David
F_p-root distribution
linear recurrence
generating function
Bernoulli polynomials
power sums
Laurent expansion
<p>Starting from the closed-form generating functions sum_r T_r(k) z^r = (1-z)^{1/z-k} prod_{m=1}^{k-1}(1-mz), we derive the linear recurrence r S_r(k) = sum_{j=1}^r c_j^{(k)} S_{r-j}(k) with S_0(k) = 1 and coefficients c_j^{(k)} = 1/(j+1) + (k-1) - sum_{m=1}^{k-1} m^j. The identity c_j^{(1)} = c_j^{(2)} = 1/(j+1) yields a fourth, purely algebraic proof of the symmetry S_r(1) = S_r(2). The recurrence is verified in exact rational arithmetic for k in {1, 2, 3, 4, 5} and r in {0, ..., 12} and provides an O(r^2)-time algorithm for computing S_r(k), compared to O(r^3) for the Vandermonde/falling-factorial method.</p>
title Linear recurrences for S_r(k) in the F_p-root Laurent expansion
topic F_p-root distribution
linear recurrence
generating function
Bernoulli polynomials
power sums
Laurent expansion
url https://doi.org/10.5281/zenodo.19700972